Question

脱式计算．①3.68×[1÷（2.10-2.09）]；②[34-0÷（17+213）]×12；③（2.4×2 23+0.1）÷10%；  

脱式计算．①3.68×[1÷（2.10-2.09）]；②[34-0÷（17+213）]×12；③（2.4×2 23+0.1）÷10%； ④（1.75+12）×（59+41）．

Answer 1

①3.68×[1÷（2.10-2.09）]
=3.68×[1÷0.01]
=3.68×100
=368

②[34-0÷（17+213）]×12
=[34-0]×12
=34×12
=408

③（2.4×2 

2

3

+0.1）÷10%      
=（6.4+0.1）÷0.1
=6.5÷0.1
=65

④（1.75+

1

2

）×（59+41）
=（1.75+

1

2

）×100
=1.75×100+

1

2

×100
=175+50
=225