
已知x^2+x-1=0,求代数式2x^3+4x^2+3的值
2个回答
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x² + x - 1 = 0
x² + x = 1
2x³ + 4x² + 3
= 2x³ + 2x² + 2x² + 3
= 2x(x² + x) + 2x² + 3
= 2x + 2x² + 3
= 2(x² + x) + 3
= 2 + 3
= 5
x² + x = 1
2x³ + 4x² + 3
= 2x³ + 2x² + 2x² + 3
= 2x(x² + x) + 2x² + 3
= 2x + 2x² + 3
= 2(x² + x) + 3
= 2 + 3
= 5
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