这道题怎么做?要详细过程,谢谢!
2015-09-01 · 知道合伙人教育行家
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(1)
x1+x2= (4k)/(4k)= 1
x1x2 = (k+1)/(4k)
(2x1-x2)(x1-2x2) = -3/2
2(x1)^2 -5x1x2 +2(x2)^2 = -3/2
2(x1+x2)^2 -9x1x2 = -3/2
2 -9(k+1)/(4k) =-3/2
9(k+1)/(4k) = 7/2
28k =18k +18
k = 9/5
(2)
x1/x2 + x2/x1 -2
=[(x1)^2 + (x2)^2]/(x1x2) -2
=[(x1+x2)^2 -2x1x2]/(x1x2) -2
=[1 -2(k+1)/(4k)]/[ (k+1)/(4k) ] -2
=(2k-2)/(k+1) -2
=-4/(k+1)
k =0 or 1 3 or -3 or -5
x1+x2= (4k)/(4k)= 1
x1x2 = (k+1)/(4k)
(2x1-x2)(x1-2x2) = -3/2
2(x1)^2 -5x1x2 +2(x2)^2 = -3/2
2(x1+x2)^2 -9x1x2 = -3/2
2 -9(k+1)/(4k) =-3/2
9(k+1)/(4k) = 7/2
28k =18k +18
k = 9/5
(2)
x1/x2 + x2/x1 -2
=[(x1)^2 + (x2)^2]/(x1x2) -2
=[(x1+x2)^2 -2x1x2]/(x1x2) -2
=[1 -2(k+1)/(4k)]/[ (k+1)/(4k) ] -2
=(2k-2)/(k+1) -2
=-4/(k+1)
k =0 or 1 3 or -3 or -5
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