Question

用分组分解法做，过程越详细越好！

Answer 1

x²-2xy-3y²+3x-5y+2
=(x²-2xy-3y²)+(3x-5y)+2
=(x+y)(x-3y)+(x+y)+2(x-3y)+2
=[(x+y)(x-3y)+2(x-3y)]+[(x+y)+2]
=(x-3y)(x+y+2)+(x+y+2)
=(x+y+2)(x-3y+1)

Answer 2

=(x+y)(x-3y)+3x-5y+2
=(x+y)(x-3y)+(x+y)+2(x-3y)+2
=(x+y)(x-3y+1)+2(x-3y+1)
=(x+y+2)(x-3y+1)

追答

md

Answer 3

x2−2xy−3y2+3x−5y+2=(x−3y)(x+y)+3x−5y+2=(x−3y)(x+y)+(x+y)+2x−6y+2=(x+y)(x−3y+1)+2(x−3y+1)=(x+y+2)(x−3y+1)

追答

望采纳，谢谢！

追问

马上，我看一下

追答

X2＝x的平方。

？？？

难道不行？

害得我白费一把功夫。

凸^-^凸