线性代数,谁可以帮忙解决一下2.3题?详解过程,谢谢
1个回答
展开全部
[ A | E ] =
2 0 1 1 0 0
1 -2 -1 0 1 0
-1 3 2 0 0 1
=
1 -2 -1 0 1 0
2 0 1 1 0 0
-1 3 2 0 0 1
=
1 -2 -1 0 1 0
0 4 3 1 -2 0
0 1 1 0 1 1
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 4 3 1 -2 0
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 0 -1 1 -6 -4
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 0 1 -1 6 4
=
1 -2 0 -1 7 4
0 1 0 1 -5 -3
0 0 1 -1 6 4
=
1 0 0 1 -3 -2
0 1 0 1 -5 -3
0 0 1 -1 6 4
A^(-1) =
1 -3 -2
1 -5 -3
-1 6 4
2 0 1 1 0 0
1 -2 -1 0 1 0
-1 3 2 0 0 1
=
1 -2 -1 0 1 0
2 0 1 1 0 0
-1 3 2 0 0 1
=
1 -2 -1 0 1 0
0 4 3 1 -2 0
0 1 1 0 1 1
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 4 3 1 -2 0
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 0 -1 1 -6 -4
=
1 -2 -1 0 1 0
0 1 1 0 1 1
0 0 1 -1 6 4
=
1 -2 0 -1 7 4
0 1 0 1 -5 -3
0 0 1 -1 6 4
=
1 0 0 1 -3 -2
0 1 0 1 -5 -3
0 0 1 -1 6 4
A^(-1) =
1 -3 -2
1 -5 -3
-1 6 4
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询