x=1/（t+1）,y=t/(t-1)²。求它的导数dy/dx
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dy/dt
=[(t-1)^2-t*2(t-1)]/(t-1)^4
=(t^2-2t+1-2t^2+2t)/(t-1)^4
=(t^2-2t^2+1)/(t-1)^4
=-(t-1)(t+1)/(t-1)^4
=-(t+1)/(t-1)^3
dx/dt
=-1/(t+1)^2
所以：
dy/dx
=[(t+1)/(t-1)^3]/[1/(t+1)^2]
=(t+1)^3/(t-1)^3.
=[(t+1)/(t-1)]^3.
=[(t-1)^2-t*2(t-1)]/(t-1)^4
=(t^2-2t+1-2t^2+2t)/(t-1)^4
=(t^2-2t^2+1)/(t-1)^4
=-(t-1)(t+1)/(t-1)^4
=-(t+1)/(t-1)^3
dx/dt
=-1/(t+1)^2
所以：
dy/dx
=[(t+1)/(t-1)^3]/[1/(t+1)^2]
=(t+1)^3/(t-1)^3.
=[(t+1)/(t-1)]^3.
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