Question

急！ajax上传图片，PHP获取不到

ajax上传formdata，PHP端接收不到数据，打印数组是空的
代码如下：
<div>
<form action="" id="formdata" enctype="multipart/form-data" method="post">
<div id="upload" class="btn btn-primary">选择图片</div>
<div class="btn btn-success" id="uploadImg">上传</div>
<input id="file" type="file" multiple style="display:none">
<div class="gallery" id="gallery"></div>
</form>
</div>
<script>
$("#uploadImg").click(function(){
var files = that.files;
var uploadFile = new FormData($("#formdata")[0]);
for(var i=0;i<files.length;i++){
uploadFile.append('imgs[]',files[i]);
}

if("undefined" != typeof(uploadFile) && uploadFile != null && uploadFile != ""){
alert("1");
$.ajax({
url:'uploadimg/upimg.php',
type:'POST',
data:uploadFile,
//async: false,
cache: false,
contentType: false, //不设置内容类型
processData: false, //不处理数据

success:function(data){
alert(data);
},
error:function(){
alert("上传失败！");
}
})
}else {

}
})

</script>
php代码：
<?php

$files=$_FILES['uploadFile'];
echo 'FILES:'.var_dump($_FILES);
echo 'POST:'.var_dump($_POST);
？>
输出结果：
<br />
<b>Notice</b>: Undefined index: uploadFile in <b>C:\phpStudy\WWW\wx-xcx\admin\en\uploadimg\upimg.php</b> on line <b>3</b><br />
array(0) {
}
FILES:array(0) {
}
POST:

Answer 1

如何用ajax上传图片的话 我会用js把图片转成base64 然后在后端在转回来

Answer 2

var files = that.files;

that是从哪来的？

追问

我上了完整的前端代码：

追答

线上能看吗？

Answer 3

)哦对哦好好分分合合发货方