2018-11-19 · 知道合伙人教育行家
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(1) y ' = lnx + x/x - 2x = lnx+1-2x,dy = (lnx+1-2x)dx
(3)y ' = 1/tan(x/2) * [sec(x/2)]^2 * 1/2= cscx,dy = cscxdx
(5)y ' = [cosx(1-x^2) - sinx(-2x)] / (1-x^2)^2
= (cosx+2xsinx-x^2cosx) / (1-x^2)^2
dy = [(cosx+2xsinx-x^2cosx) / (1-x^2)^2]dx
(3)y ' = 1/tan(x/2) * [sec(x/2)]^2 * 1/2= cscx,dy = cscxdx
(5)y ' = [cosx(1-x^2) - sinx(-2x)] / (1-x^2)^2
= (cosx+2xsinx-x^2cosx) / (1-x^2)^2
dy = [(cosx+2xsinx-x^2cosx) / (1-x^2)^2]dx
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