求高数大神
展开全部
x^2+y^2 +z^2 -6z =0
2x +2z.∂z/∂x -6.∂z/∂x =0
∂z/∂x = x/(3-z)
//
x^2+y^2 +z^2 -6z =0
2y +2z.∂z/∂y -6∂z/∂y =0
(3-z). ∂z/∂y = y
∂z/∂y = y/(3-z)
∂^2z/∂x∂y
=∂/∂x( ∂z/∂y)
=∂/∂x [ y /(3-z) ]
=[y/(3-z)^2] .∂z/∂x
=[y/(3-z)^2]. [ x/(3-z)]
=xy/(3-z)^3
2x +2z.∂z/∂x -6.∂z/∂x =0
∂z/∂x = x/(3-z)
//
x^2+y^2 +z^2 -6z =0
2y +2z.∂z/∂y -6∂z/∂y =0
(3-z). ∂z/∂y = y
∂z/∂y = y/(3-z)
∂^2z/∂x∂y
=∂/∂x( ∂z/∂y)
=∂/∂x [ y /(3-z) ]
=[y/(3-z)^2] .∂z/∂x
=[y/(3-z)^2]. [ x/(3-z)]
=xy/(3-z)^3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询