Question

请编写函数fun()，其功能是：计算并输出下列多项式值。 S=1+1/2+1/3+1/4+…+1/n n的值要求大于1但不大于10

#include<stdio.h>
double fun(int n)
{

}
void main()
{
int n;
double s;
printf("\nInput n: ");
scanf("%d",&n);
s=fun(n);
printf("\ns=%f\n ",s);
}

Answer 1

#include<stdio.h>
double fun(int n)
{
int i;
float sum=0;
for(i=1;i<=n;i++)
sum+=1.0/i;
return sum;
}
void main()
{
int n;
double s;
printf("\nInput n: ");
scanf("%d",&n);
s=fun(n);
printf("\ns=%f\n ",s);
}
如有精度需求，可以改！

Answer 2

#include<stdio.h>
double fun(int n)
{
double sum = 0;
double i;
for (i = 1; i <= n; i++)
sum += 1.0/i;
return sum;
}
void main()
{
int n;
double s;
printf("\nInput n: ");
scanf("%d",&n);
s=fun(n);
printf("\ns = %f\n ",s);
}