求定积分 定积分（0,派）dt(sint/2)^3
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S(0,pai)(sin(t/2))^3dt
=S(0,pai)(sin(t/2))^2 *sin(t/2)dt
=-2S(0,pai)(sin(t/2))^2 dcos(t/2)
=-2S(0,pai)(1-cos^2 (t/2))dcos(t/2)
=-2[cos(t/2)-1/3*cos^3 (t/2)](0,pai)
=-2[(0-0)-(1-1/3)]
=4/3
=S(0,pai)(sin(t/2))^2 *sin(t/2)dt
=-2S(0,pai)(sin(t/2))^2 dcos(t/2)
=-2S(0,pai)(1-cos^2 (t/2))dcos(t/2)
=-2[cos(t/2)-1/3*cos^3 (t/2)](0,pai)
=-2[(0-0)-(1-1/3)]
=4/3
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