（x+y）(x-1)-xy-y^2 怎么因式分解?？
1个回答
展开全部
（x+y）(x-1)-xy-y^2
=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),8,xx+xy-x-y-xy-yy
=xx-x-y-yy
=(x-y)(x+y)-(x+y)
=(x-y-1)(x+y),2,=x2-x+xy-y-xy-y2
=x2-x-y-y2
=(x-y)(x+y)-(x+y)
=(x+y)(x-y-1),2,(x+y)*(x-1)-x*y-y*y=(x+y)*(x-1)-(x+y)*y=(x+y)*(x-y-1),2,（x+y）(x-1)-xy-y^2
=（x+y）(x-1)-y(x+y)
=（x+y）(x-y-1),1,（x+y）(x-1)-xy-y^2
=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),0,=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),0,
=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),8,xx+xy-x-y-xy-yy
=xx-x-y-yy
=(x-y)(x+y)-(x+y)
=(x-y-1)(x+y),2,=x2-x+xy-y-xy-y2
=x2-x-y-y2
=(x-y)(x+y)-(x+y)
=(x+y)(x-y-1),2,(x+y)*(x-1)-x*y-y*y=(x+y)*(x-1)-(x+y)*y=(x+y)*(x-y-1),2,（x+y）(x-1)-xy-y^2
=（x+y）(x-1)-y(x+y)
=（x+y）(x-y-1),1,（x+y）(x-1)-xy-y^2
=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),0,=x^2-x+xy-y-xy-y^2
=(x^2-y^2)-(x+y)
=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1),0,
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
