Question

杭电acm 2054 ，一直wa，难道漏考虑情况了？？？

Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input
each test case contains two numbers A and B.

Output
for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input
1 2
2 2
3 3
4 3

Sample Output
NO
YES
YES
NO

提交代码：
#include<iostream>
#include<string>
using namespace std;
int main()
{
char a[100000];
char b[100000];
char a2[100000];
char b2[100000];
memset(a,'\0',sizeof(a));
memset(b,'\0',sizeof(b));
memset(a2,'\0',sizeof(a2));
memset(b2,'\0',sizeof(b2));
cin>>a>>b;
int j = 0;

while(a[j]=='0') //计算前面有多少个0
{
j++;
}
int i = 0;

while(a[j]!='\0') //前面0删了
{
a2[i] = a[j];
i++;
j++;
}
i = i-1;
if(strchr(a2,'.')) //有小数点把后面0删了
{
while(a2[i]=='0')
{
a2[i] = '\0';
i--;
}
if(a2[i]=='.')a2[i]='\0'; //后面全是0把小数点删了
}//---------------------------------------------------------------------
j = 0;

while(b[j]=='0') //---------------同理
{
j++;
}
i = 0;
while(b[j]!='\0')
{
b2[i] = b[j];
i++;
j++;
}
i = i-1;
if(strchr(b2,'.'))
{
while(b2[i]=='0')
{
b2[i] = '\0';
i--;
}
if(b2[i]=='.')b2[i]='\0';
}
int c = strcmp(a2,b2); //两个字符串是否相等
if(c==0)cout<<"YES"<<endl;
else cout<<"NO"<<endl;
return 0;

}

Answer 1

#include<iostream>
#include<string>
using namespace std;
int main()
{
	char a[100000];
	char b[100000];
	char a2[100000];
	char b2[100000];
	memset(a,'\0',sizeof(a));
	memset(b,'\0',sizeof(b));
	while(cin>>a>>b){//一直读入直到文件结尾
	memset(a2,'\0',sizeof(a2));
	memset(b2,'\0',sizeof(b2));
	
	int j = 0;
	int flag1=0,flag2=0;//记录两个字符串的符号，要考虑正负号 +0.0 -0.0
	if(a[0]=='+'){
		flag1=0;
		strcpy(a,a+1);
	}
	if(a[0]=='-'){
		flag1=1;
		strcpy(a,a+1);
	}
	if(b[0]=='+'){
		flag2=0;
		strcpy(b,b+1);
	}
	if(b[0]=='-'){
		flag2=1;
		strcpy(b,b+1);
	}
	while(a[j]=='0')                         //计算前面有多少个0
	{
		j++;
	}
	int i = 0;
	
    while(a[j]!='\0')                       //前面0删了
	{
		a2[i] = a[j];
		i++;
		j++;
	}
	i = i-1;
	if(strchr(a2,'.'))                //有小数点把后面0删了
	{
		while(a2[i]=='0')
		{
			a2[i] = '\0';
			i--;
		}    
		if(a2[i]=='.')a2[i]='\0';        //后面全是0把小数点删了
	}//---------------------------------------------------------------------
	j = 0;
	
	while(b[j]=='0')                    //---------------同理
	{
		j++;
	}
	i = 0;
	while(b[j]!='\0')
	{
		b2[i] = b[j];
		i++;
		j++;
	}
	i = i-1;
	if(strchr(b2,'.'))
	{
		while(b2[i]=='0')
		{
			b2[i] = '\0';
			i--;
		}
		if(b2[i]=='.')b2[i]='\0';
	}
	if(strlen(a2)==0)
		flag1=0;
	if(strlen(b2)==0)
		flag2=0;
//	cout<<a2<<" "<<b2<<endl;
	int c = strcmp(a2,b2);                           //两个字符串是否相等
	if(c==0 && flag1==flag2)cout<<"YES"<<endl;// 字符串相同并且符号一样
	else cout<<"NO"<<endl;
	}
	return 0;
	
}

这是修改后的可以AC的代码，欢迎交流哈，满意请采纳。

Answer 2

你比较 A B 两个字符串的时候没有考虑符号啊，比如 2 和+2 ， 0 和+0 和-0