Question

(7/4-7/8-7/12)/(-7/8)+(-8/3)=（要过程）

Answer 1

(7/4-7/8-7/12)/(-7/8)+(-8/3)=（要过程）
解:原式=(7/4-7/8-7/12)/(-7/8)+(-8/3)
=((7*6-7*3-7*2)/24)/(-7/8)+(-8/3)
=(7/24)*(-8/7)-8/3
=-8/24-8/3
=-9/3
=-3

Answer 2

6÷[(9+8+7)÷8]=2
6÷(9+8-7-8)=3
6-(9+8-7-8)=4
6-[9-(8-7)*8]=5
6+9-8+7-8=6
6+9-(8-7)*8=7
6+9-8-7+8=8
(6+9)÷(8+7)+8=9
-6+9+8+7-8=10（用到负数了）
1和10做不出来了，是否有解值得怀疑

Answer 3

(7/4-7/8-7/12)/(-7/8)-(-2)^2/(3/4)
=-7/4÷7/8+7/8÷7/8+7/12÷7/8-4÷3/4
=-2+1+2/3-16/3
=-17/3

Answer 4

10*10-9*9+8*8-7*7+6*6-5*5+4*4-3*3+2*2-1*1
=(10+9)*(10-9)+(8+7)*(8-7)+(6+5)*(6-5)+(4+3)*(4-3)+(2+1)*(2-1)
=19*1+15*1+11*1+7*1+3*1
=19+15+11+7+3
=55