Question

C语言中怎么把一个数字存放在内存的指定地址上 内存地址是用malloc分配的

Answer 1

1.定义int a
2。定义指针 p int *p ; p=a
2.强制转换 malloc 分配的地址类型 使它等于p
p= (int *) malloc()

Answer 2

C语言：
int* ptr = (int*)malloc(sizeof(int)); //分配内存
*ptr = 100; //对ptr指向的内存赋值100
free(ptr); //用完之后释放

C++
int* ptr = new int;
*ptr = 100;
delete ptr;

Win32程序可以调用Windows API:
int* ptr = (int*)HeapAlloc(GetProcessHeap(), HEAP_ZERO_MEMORY, sizeof(int));
*ptr = 100;
HeapFree(ptr);

Answer 3

int n;
char *p;
p = (char *)malloc(100);
n=2011;
memcpy(p,&n,sizeof(n));

Answer 4

int *p = (int *)malloc(100);