Question

初一10道去分母 一元一次方程计算题

Answer 1

/ 是 分数线

11x/2+(64-2x)/6=(100-9x)/8
15-(8-5x)/2=7x/3+(4-3x)/4
3(x-7)/4-2[9-4(2-x)]/9=22/3
3/2[2/3(1/4x-1)-2]-x/9=2/5
2x+7^2/2=157/5
5x*56+(-3^3-x)]/9=5
89x/3-5^2-(8-5x)/5=541
x+7-(-36+8^2)/2=8+7^4/3
a-7-98+7a=3.2*5a
89/2+35/6x=3*9+2^3/5+7x
3X+189/3=521/2
4Y+119*^3=22/11
7(2x-1)-3(4x-1)/9=[4(3x+2)-1]/9
[(5y+1)+ (1-y)]/2= [(9y+1)+ (1-3y)]/3
[-6(-7^4*8)-4]/5=(x+2)/6
2/3*8*1/4x=89/2
20%/5+(1-20%)(320-x)/9=320×40%/3
2(x-2)/6+2/9=(x+1)/2
2(x-2)/2-3(4x-1)/3=9(1-x)/2

是不是要小数的呀？？
就找到这些、、

Answer 2

/ 是 分数线

11x/2+(64-2x)/6=(100-9x)/8
15-(8-5x)/2=7x/3+(4-3x)/4
3(x-7)/4-2[9-4(2-x)]/9=22/3
3/2[2/3(1/4x-1)-2]-x/9=2/5
2x+7^2/2=157/5
5x*56+(-3^3-x)]/9=5
89x/3-5^2-(8-5x)/5=541
x+7-(-36+8^2)/2=8+7^4/3
a-7-98+7a=3.2*5a
89/2+35/6x=3*9+2^3/5+7x
3X+189/3=521/2
4Y+119*^3=22/11
7(2x-1)-3(4x-1)/9=[4(3x+2)-1]/9
[(5y+1)+ (1-y)]/2= [(9y+1)+ (1-3y)]/3
[-6(-7^4*8)-4]/5=(x+2)/6
2/3*8*1/4x=89/2
20%/5+(1-20%)(320-x)/9=320×40%/3
2(x-2)/6+2/9=(x+1)/2
2(x-2)/2-3(4x-1)/3=9(1-x)/2