
(2²+1)(2四次方+1)(2八次方+1)…(2六十四次方+1)等于?
2个回答
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重复利用平方差公式
(2^2+1)(2^4+1)(2^8+1)...(2^64+1)
=(2^2-1)(2^2+1)(2^4+1)...(2^64+1)/(2^2-1)
=(2^4-1)(2^4+1)...(2^64+1)/3
=...
=(2^64-1)(2^64+1)/3
=(2^128-1)/3
(2^2+1)(2^4+1)(2^8+1)...(2^64+1)
=(2^2-1)(2^2+1)(2^4+1)...(2^64+1)/(2^2-1)
=(2^4-1)(2^4+1)...(2^64+1)/3
=...
=(2^64-1)(2^64+1)/3
=(2^128-1)/3
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