Question

求解,数学分式

{(X1-X2)/[(X1+X2)/2]*100%}/{(Y1-Y2)/[(Y1+Y2)/2]*100%}=?

Y1=3X1
Y2=3X2
有过程最好

Answer 1

原式={(X1-X2)/[(X1+X2)/2]}/{(Y1-Y2)/[(Y1+Y2)/2]}
=[2(X1-X2)/(X1+X2)]/{2(3X1-3X2)/(3X1+3X2)}
=[(X1-X2)/(X1+X2)]/{(X1-X2)/(X1+X2)}
=(X1-X2)/(X1+X2)*(X1+X2)/(X1-X2)
=1