Question

Java中，怎么将一段浮点数值转换成人民币格式？例如将12004567.866转换成 ：壹千贰百万

Java中，怎么将一段浮点数值转换成人民币格式？例如将12004567.866转换成 ：壹千贰百万肆千伍百陆拾柒元 捌角陆分？
新手学Java，求教。最好有注释。十分感谢了。

Answer 1

直接通过以下接口类方法实现即可：importjava.math.BigDecimal;/***金额工具类**@authorzn**@Date2013-2-1*@Emailzn.share@gmail.com*/publicclassMoneyUtil{privatestaticfinalintDFT_SCALE=2;/**大写数字*/privatestaticfinalString[]NUMBERS={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};/**整数部分的单位*/privatestaticfinalString[]IUNIT={"元","拾","佰","仟","万","拾","佰","仟","亿","拾","佰","仟","万","拾","佰","仟"};/**小数部分的单位*/privatestaticfinalString[]DUNIT={"角","分","厘"};/***得到大写金额。*/publicstaticStringtoChinese(Stringstr){str=str.replaceAll(",","");//去掉","StringintegerStr;//整数部分数字StringdecimalStr;//小数部分数字//初始化：分离整数部分和小数部分if(str.indexOf(".")>0){integerStr=str.substring(0,str.indexOf("."));decimalStr=str.substring(str.indexOf(".")+1);}elseif(str.indexOf(".")==0){integerStr="";decimalStr=str.substring(1);}else{integerStr=str;decimalStr="";}//integerStr去掉首0，不必去掉decimalStr的尾0(超出部分舍去)if(!integerStr.equals("")){integerStr=Long.toString(Long.parseLong(integerStr));if(integerStr.equals("0")){integerStr="";}}//overflow超出处理能力，直接返回if(integerStr.length()>IUNIT.length){System.out.println(str+":超出处理能力");returnstr;}int[]integers=toArray(integerStr);//整数部分数字booleanisMust5=isMust5(integerStr);//设置万单位int[]decimals=toArray(decimalStr);//小数部分数字returngetChineseInteger(integers,isMust5)+getChineseDecimal(decimals);}/***整数部分和小数部分转换为数组，从高位至低位*/privatestaticint[]toArray(Stringnumber){int[]array=newint[number.length()];for(inti=0;i1&&integers[i+1]!=0)key+=NUMBERS[0];}chineseInteger.append(integers[i]==0?key:(NUMBERS[integers[i]]+IUNIT[length-i-1]));}returnchineseInteger.toString();}/***得到中文金额的小数部分。*/privatestaticStringgetChineseDecimal(int[]decimals){StringBufferchineseDecimal=newStringBuffer("");for(inti=0;i4){StringsubInteger="";if(length>8){//TODO12-9-17//取得从低位数，第5到第8位的字串subInteger=integerStr.substring(length-8,length-4);}else{subInteger=integerStr.substring(0,length-4);}returnInteger.parseInt(subInteger)>0;}else{returnfalse;}}/***BigDecimal相乘,四舍五入保留0位**@parama*@paramb*@returna*b*/publicstaticBigDecimalmutiply(Stringa,Stringb,introundingMode){BigDecimalbd=newBigDecimal(a);returnbd.multiply(newBigDecimal(b)).setScale(DFT_SCALE,roundingMode);}/***BigDecimal相除,四舍五入保留两位**@parama*@paramb*@returna/b*/publicstaticBigDecimaldiv(Stringa,Stringb,introundingMode){BigDecimaldecimal1=newBigDecimal(a);BigDecimaldecimal2=newBigDecimal(b);returndecimal1.divide(decimal2,DFT_SCALE,roundingMode);}/***BigDecimal相加,四舍五入保留两位**@parama*@paramb*@returna+b*/publicstaticBigDecimalsum(Stringa,Stringb,introundingMode){BigDecimaldecimal1=newBigDecimal(a);BigDecimaldecimal2=newBigDecimal(b);//DecimalFormatformat=newDecimalFormat("#0.00");returndecimal1.add(decimal2).setScale(DFT_SCALE,roundingMode);}/***BigDecimal相减,四舍五入保留两位**@parama*@paramb*@returna+b*/publicstaticBigDecimalsub(Stringa,Stringb,introundingMode){BigDecimaldecimal1=newBigDecimal(a);BigDecimaldecimal2=newBigDecimal(b);//DecimalFormatformat=newDecimalFormat("#0.00");returndecimal1.subtract(decimal2).setScale(DFT_SCALE,roundingMode);}/***100.00为10000**@parama*@return*/publicstaticBigDecimalformat(Stringa,introundingMode){returnnewBigDecimal(a).multiply(newBigDecimal(100)).setScale(0,roundingMode);}publicstaticvoidmain(String[]args){Stringnumber="54452";System.out.println(number+""+MoneyUtil.toChinese(number));number="30200";System.out.println(number+""+MoneyUtil.toChinese(number));number="30000.05";System.out.println(number+""+MoneyUtil.toChinese(number));number="30000.00";System.out.println(number+""+MoneyUtil.toChinese(number));}}备注：最后面的main方法是具体的调用。