Question

C语言 写一函数，求出字符串的长度，在主函数中输入字符串，并输出其长度，不要用strlen函数

Answer 1

main你自己写吧，函数代码如下：
slen(char s[]){
int n=0;
while (s[n]) n++;
return(n-1);
}

Answer 2

/*************添加注释***************/
#include<stdio.h>
#define SIZE 200
int length(char *src)
{
char *p;
int count = 0;
p = src;
while(*p++){
count++;
}
return count;

}
int main(void)
{
int len;
char a[SIZE];
printf("\nplease input a string\n");
gets(a);
len = length(a);
printf("\nthe diatance of string is %d\n",len);
return 0;
}

Answer 3

#include <stdio.h>
main()
{
char a;
int b=0;
printf("输入字符串：")；
scanf("%s",&a);
if(a!=\0) b++;
printf("%d',b);
}

Answer 4

int stringlength(char s[])
{
int i=0;
while(s[i]!='\0')
i++;
return i-1;
}

Answer 5

int compute(char *sour)
{
int n=0;
char *p=sour;
while(p)
{
p++;
n++;
}
return n;
}
int main(int argc, char **argv)
{
int nlen=0;
char ch[1024] = "abc";
nlen = compute(ch);
}