如下图多示,四边形ABCD是一个轴对称图形。如果纵轴和横轴上相邻的两个白自然
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<table style="width:100%"> <tbody> <tr> <td> ∵四边形ABCD是轴对称图形,直线AC是对称轴,
∴∠BAC=∠DAC,∠BCA=∠DCA,
∴∠BAC+∠BCA=<span mathtag="math"> <table style="display:inline-table;vertical-align:middle" cellpadding="-1" cellspacing="-1"> <tbody> <tr> <td style="border-bottom:1px solid black"> 1</td> </tr> <tr> <td> 2 </span> (∠BAD+∠BCD),
∵∠BAD+∠BCD=210°,
∴∠BAC+∠BCA=<span mathtag="math"> <table style="display:inline-table;vertical-align:middle" cellpadding="-1" cellspacing="-1"> <tbody> <tr> <td style="border-bottom:1px solid black"> 1</td> </tr> <tr> <td> 2 </span> ×210°=105°.
故选B.
∴∠BAC=∠DAC,∠BCA=∠DCA,
∴∠BAC+∠BCA=<span mathtag="math"> <table style="display:inline-table;vertical-align:middle" cellpadding="-1" cellspacing="-1"> <tbody> <tr> <td style="border-bottom:1px solid black"> 1</td> </tr> <tr> <td> 2 </span> (∠BAD+∠BCD),
∵∠BAD+∠BCD=210°,
∴∠BAC+∠BCA=<span mathtag="math"> <table style="display:inline-table;vertical-align:middle" cellpadding="-1" cellspacing="-1"> <tbody> <tr> <td style="border-bottom:1px solid black"> 1</td> </tr> <tr> <td> 2 </span> ×210°=105°.
故选B.
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