2个回答
展开全部
A=max{ a1,a2,...,am }
consider
L = lim(x->∞) [ (a1)^x +(a2)^x +...+(am)^x ]^(1/x)
lnL
= lim(x->∞) ln[ (a1)^x +(a2)^x +...+(am)^x ] /x (∞/∞)
= lim(x->∞) { (lna1)(a1)^x +(lna2)(a2)^x +...+(lnam)(am)^x }
/ [ (a1)^x +(a2)^x +...+(am)^x ]
= lim(x->∞) { (lna1)(a1/A)^x +(lna2)(a2/A)^x +...+(lnam)(am/A)^x }
/ [ (a1/A)^x +(a2/A)^x +...+(am/A)^x ]
= lnA
=> L = A
=>lim(n->∞) [ (a1)^n +(a2)^n +...+(am)^n ]^(1/n) = A
consider
L = lim(x->∞) [ (a1)^x +(a2)^x +...+(am)^x ]^(1/x)
lnL
= lim(x->∞) ln[ (a1)^x +(a2)^x +...+(am)^x ] /x (∞/∞)
= lim(x->∞) { (lna1)(a1)^x +(lna2)(a2)^x +...+(lnam)(am)^x }
/ [ (a1)^x +(a2)^x +...+(am)^x ]
= lim(x->∞) { (lna1)(a1/A)^x +(lna2)(a2/A)^x +...+(lnam)(am/A)^x }
/ [ (a1/A)^x +(a2/A)^x +...+(am/A)^x ]
= lnA
=> L = A
=>lim(n->∞) [ (a1)^n +(a2)^n +...+(am)^n ]^(1/n) = A
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询