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12.∫(cos20x)^3dx
=(1/20)[sin20x-(1/3)(sin20x)^3]+c.
注：设u=sain2x.
15.∫(sinx)^2(cosx)^2dx
=(1/4)∫(sin2x)^2dx
=(1/8)∫(1-cos4x)dx
=(1/8)[x-(1/4)sin4x]+c.
余者仿上。
=(1/20)[sin20x-(1/3)(sin20x)^3]+c.
注：设u=sain2x.
15.∫(sinx)^2(cosx)^2dx
=(1/4)∫(sin2x)^2dx
=(1/8)∫(1-cos4x)dx
=(1/8)[x-(1/4)sin4x]+c.
余者仿上。
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三角函数
都忘光了
哎
老了
待我看看先
能解答不
都忘光了
哎
老了
待我看看先
能解答不
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