c语言,输入两个点,用星星打成一条直线。求源代码?
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我用VC6实现了。关键代码如下:
1、获得五个外顶点的坐标:
int m_xw[5]; //5个X外顶点坐标
int m_yw[5]; //5个Y外顶点坐标
void CMyTestView::getCoord()
{
int c = 360 / 5; //角度
int r = 150;
for (int i = 0; i < 5; i++)
{
m_xw[i] = (int) (cos(i * c * PI / 30 - PI / 2) * (r) + r);
m_yw[i] = (int) (sin(i * c * PI / 30 - PI / 2) * (r) + r);
}
}
2、画线段:
在构造函数中调用求顶点坐标的函数求顶点坐标:
this->getCoord();
然后直接在绘图函数中添加如下代码:
void CMyTestView::OnDraw(CDC* pDC)
{
CMyTestDoc* pDoc = GetDocument();
ASSERT_VALID(pDoc);
// TODO: add draw code for native data here
pDC->MoveTo(m_xw[4], m_yw[4]);
pDC->LineTo(m_xw[1], m_yw[1]);
pDC->LineTo(m_xw[3], m_yw[3]);
pDC->LineTo(m_xw[0], m_yw[0]);
pDC->LineTo(m_xw[2], m_yw[2]);
pDC->LineTo(m_xw[4], m_yw[4]);
}
//运行结果
1、获得五个外顶点的坐标:
int m_xw[5]; //5个X外顶点坐标
int m_yw[5]; //5个Y外顶点坐标
void CMyTestView::getCoord()
{
int c = 360 / 5; //角度
int r = 150;
for (int i = 0; i < 5; i++)
{
m_xw[i] = (int) (cos(i * c * PI / 30 - PI / 2) * (r) + r);
m_yw[i] = (int) (sin(i * c * PI / 30 - PI / 2) * (r) + r);
}
}
2、画线段:
在构造函数中调用求顶点坐标的函数求顶点坐标:
this->getCoord();
然后直接在绘图函数中添加如下代码:
void CMyTestView::OnDraw(CDC* pDC)
{
CMyTestDoc* pDoc = GetDocument();
ASSERT_VALID(pDoc);
// TODO: add draw code for native data here
pDC->MoveTo(m_xw[4], m_yw[4]);
pDC->LineTo(m_xw[1], m_yw[1]);
pDC->LineTo(m_xw[3], m_yw[3]);
pDC->LineTo(m_xw[0], m_yw[0]);
pDC->LineTo(m_xw[2], m_yw[2]);
pDC->LineTo(m_xw[4], m_yw[4]);
}
//运行结果
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