java中read(byte[])找不到符号怎么办?
1个回答
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java.io.DataInputStream.readByte() 方法读取并返回一个单一的输入字节。该字节的范围是从-128到127之间的有符号值。
示例演示java.io.DataInputStream.readByte()方法的用法。
import java.io.ByteArrayInputStream;
import java.io.DataInputStream;
import java.io.IOException;
import java.io.InputStream;
public class DataInputStreamDemo {
public static void main(String[] args) throws IOException {
InputStream is = null;
DataInputStream dis = null;
byte[] buf = {65, 0, 0, 68, 69};
try{
// create new byte array input stream
is = new ByteArrayInputStream(buf);
// create data input stream
dis = new DataInputStream(is);
// readBoolean till the data available to read
while( dis.available() >0)
{
// read one single byte
byte b = dis.readByte();
// print the byte
System.out.print(b+" ");
}
}catch(Exception e){
// if any I/O error occurs
e.printStackTrace();
}finally{
// releases any associated system files with this stream
if(is!=null)
is.close();
if(dis!=null)
dis.close();
}
}
}
让我们编译和运行上面的程序,这将产生以下结果:
65 0 0 68 69
示例演示java.io.DataInputStream.readByte()方法的用法。
import java.io.ByteArrayInputStream;
import java.io.DataInputStream;
import java.io.IOException;
import java.io.InputStream;
public class DataInputStreamDemo {
public static void main(String[] args) throws IOException {
InputStream is = null;
DataInputStream dis = null;
byte[] buf = {65, 0, 0, 68, 69};
try{
// create new byte array input stream
is = new ByteArrayInputStream(buf);
// create data input stream
dis = new DataInputStream(is);
// readBoolean till the data available to read
while( dis.available() >0)
{
// read one single byte
byte b = dis.readByte();
// print the byte
System.out.print(b+" ");
}
}catch(Exception e){
// if any I/O error occurs
e.printStackTrace();
}finally{
// releases any associated system files with this stream
if(is!=null)
is.close();
if(dis!=null)
dis.close();
}
}
}
让我们编译和运行上面的程序,这将产生以下结果:
65 0 0 68 69
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