Question

求EDA八路抢答器课程设计

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Answer 1

做过六路的抢答器设计，自己把这个再改改吧
library ieee;
use ieee.std_logic_1164.all;
entity liulu is
port(set，clk，d1，d2，d3，d4，d5，d6:in std_logic; --定义六个输入一个时钟一个复位
q:out std_logic_vector(3 downto 0); --合法抢答时的输出
fq:out std_logic_vector(5 downto 0); --非法抢答时的输出
selected: out std_logic); --判断是否有合法抢答信号
end liulu;
architecture liulu of liulu is
signal deny: std_logic; --定义锁存信号
begin
selected<=deny;
process(d1，d2，d3，d4，d5，d6，set)
variable tmp1，tmp3:std_logic_vector(5 downto 0); --定义抢答时中间变量
variable tmp2:std_logic; --定义判断是否有抢答信号的变量
begin
tmp1:=d1 & d2 & d3 & d4 & d5 & d6;
tmp2:=d1 or d2 or d3 or d4 or d5 or d6;
tmp3:=(d1 and clk)&(d2 and clk)&(d3 and clk)&(d4 and clk)&(d5 and clk)&(d6 and clk);
fq<="000000"; --定义非法抢答时输出的初始状态
if set='0' then
deny<='0';
tmp1:="000000";
q<="0000"; --定义合法抢答时输出的初始状态

if tmp2='1' then --判断是否有非法抢答
fq<= tmp3;
end if;
elsif deny='0' then --合法抢答时译码输出
case tmp1 is
when "100000"=>q<="0001" ;deny<='1';
when "010000"=>q<="0010" ;deny<='1';
when "001000"=>q<="0011" ;deny<='1';
when "000100"=>q<="0100" ;deny<='1';
when "000010"=>q<="0101" ;deny<='1';
when "000001"=>q<="0110" ;deny<='1';
when others=>q<="0000";
end case;
end if;
end process;
end liulu;