Question

C语言编程:用函数求Cmn=m!/(n!(m-n)!)

Answer 1

#include <iostream>
using namespace std;
int jiecheng(int n)
{int sum=1;
if(n<=0)
return 0;
for(int i=1;i<=n;i++)
{
sum*=i;
}
return sum;
}
int main()
{int n,m,Cmn;
cin>>n>>m;
Cmn=jiecheng(m)/(jiecheng(n)*jiecheng(m-n));
cout<<Cmn;
return 0;
}
注意输入时n 和m之间有空格啊。

Answer 2

int C(int m,int n)
{
double t=1,i;
for (i=1;i<=n;i++)
{
t*=(i+m-n)/i;
}
return t;
}