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弦长L=3.3米,高H=0.5米,求弧长C?
弧半径为R,弧所对的圆心角为A。
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=0.5/2+3.3^2/(8*0.5)
=2.9725米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((3.3/2)/2.9725)
=67.434度
=67.434*PI/180
=1.17694弧度
C=A*R
=1.17694*2.9725
=3.4984米
弧半径为R,弧所对的圆心角为A。
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=0.5/2+3.3^2/(8*0.5)
=2.9725米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((3.3/2)/2.9725)
=67.434度
=67.434*PI/180
=1.17694弧度
C=A*R
=1.17694*2.9725
=3.4984米
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