计算(24x^4y^2+12x^3y^3-8x^2y^4)/6x^2y^2
1个回答
2011-01-03
展开全部
分别展开,x和y的幂次方相消就可以了
(24x^4y^2)/(6x^2y^2)+(12x^3y^3)/(6x^2y^2)-(8x^2y^4)/(6x^2y^2)
=4x^2y^0+2x^1y^1-4/3x^0y^2
=4x^2+2xy-4/3y^2
=2(2x^2+xy-2/3y^2)
(24x^4y^2)/(6x^2y^2)+(12x^3y^3)/(6x^2y^2)-(8x^2y^4)/(6x^2y^2)
=4x^2y^0+2x^1y^1-4/3x^0y^2
=4x^2+2xy-4/3y^2
=2(2x^2+xy-2/3y^2)
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