Question

(a+b)4+(a2-b2)2+(a-b)4因式分解 4是四次方~

没有错误的~

Answer 1

(a+b)^4+(a2-b2)^2+(a-b)^4
=[(a+b)^4+2(a+b)^2*(a-b)^2+(a-b)^4]-2(a+b)^2*(a-b)^2+(a2-b2)^2
=[(a+b)^2+(a-b)^2]^2-(a2-b2)^2
=[2a^2+2b^2]^2-(a2-b2)^2
=[(2a^2+2b^2)+(a^2-b^2)][2a^2+2b^2-(a^2-b^2)]
=(3a^2+b^2)(a^2+3b^2).

Answer 2

我估计你少写了一个系数
(a+b)^4+2(a^2-b^2)^2+(a-b)^4=(a+b)^4+2(a+b)^2*(a-b)^2+(a-b)^4
=[(a+b)^2+(a-b)^2]^2=(2a^2+2b^2)^2=4(a^2+b^2)^2

Answer 3

(a+b)4+(a2-b2)2+(a-b)4
=(a+b)4+(a+b)2(a-b)2+(a-b)4
=(a+b)4+2(a+b)2(a-b)2+(a-b)4-(a+b)2(a-b)2
=【(a+b)2+(a-b)2】2-(a2-b2)2
=（2a2+2b2）2-(a2-b2)2
=（2a2+2b2+a2-b2）（2a2+2b2-a2+b2)
=(3a2+b2)(a2+3b2)

Answer 4

不会