Question

关于三角函数

有没有关于三角函数的和差之类的关系的公式，现在到了大学那东西不怎么用基本忘了，但是考试了偶尔会用到，知道自己打公式肯定累，能给个链接也可以，最好是有倍数关系之类的，要是能有三角函数微积分最好

Answer 1

公式sin(a+b)=sinacosb+cosasinb
公式sin(a-b)=sinacosb-cosasinb
公式cos(a+b)=cosacosb-sinasinb
公式cos(a-b)=cosacosb+sinasinb
公式tg(a+b)=(tga+tgb)/1-tgatgb
公式tg(a-b)=(tga-tgb)/1+tgatgb

倍角公式:
sin2α=2sinαcosα
cos2α=cos²(α)-sin²(α)=2cos²(α)-1=1-2sin²(α)
tan2α=2tanα/(1-tan²(α))

半角公式：
sin(α/2)=±根号[(1-cosα)/2](正负由α/2所在象限决定）
cos(α/2)=±根号[(1+cosα)/2]开二次方(正负由α/2所在象限决定）
tan(α/2)=sinα/(1+cosα)=(1-cosα)/sinα=±根号[(1-cosα）/（1+cosα）]

万能置换公式：
http://baike.baidu.com/image/7ab514d1147e68ea562c8446

sina在一二象限为+，在三四象限为-
cosa在一四象限为+，在二三象限为-
tga、ctga在一三象限为+，在二四象限为-

三角函数的其他公式：http://baike.baidu.com/view/91555.html?wtp=tt#3

微积分公式
Dx sin x=cos x
cos x = -sin x
tan x = sec2 x
cot x = -csc2 x
sec x = sec x tan x
csc x = -csc x cot x
sin x dx = -cos x + C
cos x dx = sin x + C
tan x dx = ln |sec x | + C
cot x dx = ln |sin x | + C
sec x dx = ln |sec x + tan x | + C
csc x dx = ln |csc x - cot x | + C
sin-1(-x) = -sin-1 x
cos-1(-x) = - cos-1 x
tan-1(-x) = -tan-1 x
cot-1(-x) = - cot-1 x
sec-1(-x) = - sec-1 x
csc-1(-x) = - csc-1 x
Dx sin-1 ()=
cos-1 ()=
tan-1 ()=
cot-1 ()=
sec-1 ()=
csc-1 (x/a)=
sin-1 x dx = x sin-1 x++C
cos-1 x dx = x cos-1 x-+C
tan-1 x dx = x tan-1 x- ln (1+x2)+C
cot-1 x dx = x cot-1 x+ ln (1+x2)+C
sec-1 x dx = x sec-1 x- ln |x+|+C
csc-1 x dx = x csc-1 x+ ln |x+|+C
sinh-1 ()= ln (x+) xR
cosh-1 ()=ln (x+) x≥1
tanh-1 ()=ln () |x| 1
sech-1()=ln(+)0≤x≤1
csch-1 ()=ln(+) |x| >0
Dx sinh x = cosh x
cosh x = sinh x
tanh x = sech2 x
coth x = -csch2 x
sech x = -sech x tanh x
csch x = -csch x coth x
sinh x dx = cosh x + C
cosh x dx = sinh x + C
tanh x dx = ln | cosh x |+ C
coth x dx = ln | sinh x | + C
sech x dx = -2tan-1 (e-x) + C
csch x dx = 2 ln || + C
duv = udv + vdu
duv = uv = udv + vdu
→ udv = uv - vdu
cos2θ-sin2θ=cos2θ
cos2θ+ sin2θ=1
cosh2θ-sinh2θ=1
cosh2θ+sinh2θ=cosh2θ
Dx sinh-1()=
cosh-1()=
tanh-1()=
coth-1()=
sech-1()=
csch-1(x/a)=
sinh-1 x dx = x sinh-1 x-+ C
cosh-1 x dx = x cosh-1 x-+ C
tanh-1 x dx = x tanh-1 x+ ln | 1-x2|+ C
coth-1 x dx = x coth-1 x- ln | 1-x2|+ C
sech-1 x dx = x sech-1 x- sin-1 x + C
csch-1 x dx = x csch-1 x+ sinh-1 x + C
sin 3θ=3sinθ-4sin3θ
cos3θ=4cos3θ-3cosθ
→sin3θ= (3sinθ-sin3θ)
→cos3θ= (3cosθ+cos3θ)
sin x = cos x =
sinh x = cosh x =
正弦定理:= ==2R
余弦定理: a2=b2+c2-2bc cosα
b2=a2+c2-2ac cosβ
c2=a2+b2-2ab cosγ
sin (α±β)=sin α cos β ± cos α sin β
cos (α±β)=cos α cos β sin α sin β
2 sin α cos β = sin (α+β) + sin (α-β)
2 cos α sin β = sin (α+β) - sin (α-β)
2 cos α cos β = cos (α-β) + cos (α+β)
2 sin α sin β = cos (α-β) - cos (α+β)
sin α + sin β = 2 sin (α+β) cos (α-β)
sin α - sin β = 2 cos (α+β) sin (α-β)
cos α + cos β = 2 cos (α+β) cos (α-β)
cos α - cos β = -2 sin (α+β) sin (α-β)
tan (α±β)=, cot (α±β)=
ex=1+x+++…++ …
sin x = x-+-+…++ …
cos x = 1-+-+++
ln (1+x) = x-+-+++
tan-1 x = x-+-+++
(1+x)r =1+rx+x2+x3+ -1= n
= n (n+1)
= n (n+1)(2n+1)
= [ n (n+1)]2
Γ(x) = x-1e-t dt = 22x-1dt = x-1 dt
β(m, n) =m-1(1-x)n-1 dx=22m-1x cos2n-1x dx = dx

Answer 2

http://wenku.baidu.com/view/decd7cc58bd63186bcebbc0c.html