(x²+y²-1)²-4x²y²
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解;(x²+y²-1)²-4x²y²
=(x²+y²-1)²-(2xy)²
=(x²+y²-1+2xy)(x²+y²-1-2xy)
=[(x+y)²-1][(x-y)²-1]
=[(x+y)+1][(x+y)-1][(x-y)+1][(x-y)-1]
=(x+y+1)(x+y-1)(x-y+1)(x-y-1)
=(x²+y²-1)²-(2xy)²
=(x²+y²-1+2xy)(x²+y²-1-2xy)
=[(x+y)²-1][(x-y)²-1]
=[(x+y)+1][(x+y)-1][(x-y)+1][(x-y)-1]
=(x+y+1)(x+y-1)(x-y+1)(x-y-1)
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