Question

a+b=根号下5+根号3,a-b=根号下5-根号3.求a,b的值

Answer 1

a=√5，b=√3

a+b=√5+√3……①
a-b=√5-√3……②
①+②得：2a=2*√5，故a=√5
①-②得：2b=2*√3，故b=√3

Answer 2

a=根号下5
b=根号下3

Answer 3

a+b = \sqrt{5+\sqrt{3}}
a-b = \sqrt{5-\sqrt{3}}

a^2 = (5+\sqrt{3}+2\sqrt{25-3}+5-\sqrt{3})/4
= (5+\sqrt{22})/2
a = \sqrt{(5+\sqrt{22})/2}

b^2 = (5+\sqrt{3}-2\sqrt{25-3}+5-\sqrt{3})/4
= (5-\sqrt{22})/2
b = \sqrt{(5-\sqrt{22})/2}

Answer 4

根据方程组的解，a+b=√5+√3
a-b=√5-√3
求的
a=根号下5
b=根号下3