Question

[(a-b)^2+(a+b)^2](a-b)(a+b)

Answer 1

解：原式=[(a-b)²+(a+b)²](a-b)(a+b)
=[a²-2ab+b²+a²+2ab+b²](a²-b²)
=(2a²+2b²)(a²-b²)
=2(a²+b²)(a²-b²)
=2(a⁴-b⁴)
=2a⁴-2b⁴

Answer 2

=2(a^2+b^2)(a^2-b^2)
=2a^4-2b^4

Answer 3

原式=[a^2-2ab+b^2+a^2+2ab+b^2](a^2-b^2)
=2(a^2+b^2)(a^2-b^2)
=2a^4-2b^4