Question

初一数学 因式分解

[x^2/(x-1)]-x-1
打错了，是计算

Answer 1

[x^2/(x-1)]-x-1
=[(x^2-1)+1]/(x-1)-x-1
=(x^2-1)/(x-1)+1/(x-1)-(x+1)
=(x+1)(x-1)/(x-1)+1/(x-1)-(x+1)
=(x+1)+1/(x-1)-(x+1)
=1/(x-1)

Answer 2

原式=[x^2/(x-1)]-[(x+1)(x-1)/(x-1)]
=[x^2/(x-1)]-[x^2-1/(x-1)]
=1/(x-1)