设函数y=f(x)是定义在(O,正无穷)上的函数,对定义域内的任意x,y都满足f(xy)=f(x)+f(y)
推荐于2016-12-01
展开全部
f(2)=1
f(4) = f(2*2) = f(2) + f(2) = 2
f(x)+f(x-3)<=2 = f(4)
f(x(x-3)) <= f(4)
x^2 -3x -4 <=0
-1 <= x <= 4
f(4) = f(2*2) = f(2) + f(2) = 2
f(x)+f(x-3)<=2 = f(4)
f(x(x-3)) <= f(4)
x^2 -3x -4 <=0
-1 <= x <= 4
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询