
2个回答
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原式=lim(x→0)(sinx/cosx-sinx)/(xsinxtanx)
=lim(x→0)(1-cosx)/(xtanx)*1/cosx
=lim(x→0)2sin^2(x/2)/(xtanx)
=lim(x→0)2*(x/2)^2/x^2 (x~sinx~tanx)
=1/2
=lim(x→0)(1-cosx)/(xtanx)*1/cosx
=lim(x→0)2sin^2(x/2)/(xtanx)
=lim(x→0)2*(x/2)^2/x^2 (x~sinx~tanx)
=1/2
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