因式分解:x^4+x^3-2x^2-x+1 快快快快快快快快快!!!!
展开全部
答:
x^4+x^3-2x^2-x+1
=(x^2+x-2)x^2-(x-1)
=(x-1)(x+2)x^2-(x-1)
=(x-1)(x^3+2x^2-1)
=(x-1)(x^3+x^2+x^2-1)
=(x-1)(x+1)(x^2+x-1)
x^4+x^3-2x^2-x+1
=(x^2+x-2)x^2-(x-1)
=(x-1)(x+2)x^2-(x-1)
=(x-1)(x^3+2x^2-1)
=(x-1)(x^3+x^2+x^2-1)
=(x-1)(x+1)(x^2+x-1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
原式=(x^4-2x^2+1)+(x^3-x)
=(x^2-1)^2+x(x^2-1)
=(x^2-1)(x^2+x-1)
=(x+1)(x-1)(x^2+x-1)
=(x^2-1)^2+x(x^2-1)
=(x^2-1)(x^2+x-1)
=(x+1)(x-1)(x^2+x-1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
=x^2(x^2+x-2)-x+1
=x^2(x+2)(x-1)-(x-1)
=(x-1)(x^3+2x^2-1)
=(x+1)(x-1)(x^2+x-1)
=x^2(x+2)(x-1)-(x-1)
=(x-1)(x^3+2x^2-1)
=(x+1)(x-1)(x^2+x-1)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询