Question

已知x＞0，y＞0，且x－√xy－2y＝0，求2x－√xy/y＋2√xy。

√是根号，/是分数线。请写出详细步骤，谢谢！

Answer 1

x-√xy-2y=0 (√x)-√xy-2(√y)=0 (√x-2√y)(√x+√y)=0 x>0，y>0 那么√x=2√y x=4y (2x－√xy)/(y＋2√xy) =(8y-√4y)/(y+√4y) =(8y-2y)/(y+2y) =6y/3y =2

满意请采纳