Question

求以下代码的输出结果

char a[20]="cehiknqtw";

char *s="fbla",*p;
int i,j;
for(p=s;*p; p++){
j=0;
while( *p>=a[j] && a[j] !='\0') j++;
for(i=strlen(a); i>=j; i- - > a[i+1] = a[ i ];
a [j ]= *p;
}
printf( "%s" ,a );

Answer 1

import java.util.Scanner;

public class you {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int a = sc.nextInt();
int b = sc.nextInt();
for (int i = a; i <= b; i++) {
fun(i);
System.out.println("");
}
}
public static void fun(int x) {
int k = 2;
System.out.print(x + "=");
while (k <= x) {
if (x % k == 0){
System.out.print(k);
x = x / k;
if(k<=x){
System.out.print("*");
}
} else {
k++;
}

}
}
}
请采纳答案，支持我一下。

Answer 2

把s中的字母，按顺序插入到a中，结果为：abcefhiklnqtw