化简:[(2X+1)^2-(3x-2)^2]\(1-5x)
展开全部
解:原式=(4x^2+4x+1-9x^2+12x-4)/(1-5x)
=(-5x^2+16x-3)/(1-5x)
=(5x^2-16x+3)/(5x-1)
=(5x-1)(x-3)/(5x-1)
=x-3
=(-5x^2+16x-3)/(1-5x)
=(5x^2-16x+3)/(5x-1)
=(5x-1)(x-3)/(5x-1)
=x-3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
2015-03-22
展开全部
解:原式=(4x^2+4x+1-9x^2+12x-4)/(1-5x)
=(-5x^2+16x-3)/(1-5x)
=(5x^2-16x+3)/(5x-1)
=(5x-1)(x-3)/(5x-1)
=x-3
=(-5x^2+16x-3)/(1-5x)
=(5x^2-16x+3)/(5x-1)
=(5x-1)(x-3)/(5x-1)
=x-3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询