Question

求教一个Struts2中execute()方法根据不同的返回值跳转到不同页面的问题？？

package tutorial;

import java.sql.Connection;
import java.sql.ResultSet;
import java.sql.Statement;

import com.opensymphony.xwork2.ActionSupport;

public class userinfo extends ActionSupport{
private String name;
private String password;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}

public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String execute(){
try{
Connection con = new connection().getConnection() ;
Statement stmt=con.createStatement();
String sql = "select * from userinfo where name = '" + name + "' and pwd = '" + password + "'";
ResultSet rs=stmt.executeQuery(sql);
if(rs.next()){
return SUCCESS;
}else{
return ERROR;
}
}catch(Exception e){

}
return SUCCESS;

}
}

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<package name="tutorial" extends="struts-default">
<action name="userinfo" class="tutorial.userinfo">
<result name="SUCCESS">/welcome.jsp</result>
<result name="ERROR">/err.jsp</result>
</action>
</package>
</struts>
这是一个简单的登录界面，想根据登录是否成功返回不同的值，跳转到不同的界面，可是却一直报错

Answer 1

将return SUCCESS改为"SUCCESS"
没用字符串而是用的父类的变量SUCCESS，它的值是小写的"success"