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∫x/(x^2-x-2) dx
=∫x/[(x-2)(x+1)] dx
=(1/3)∫[1/(x+1)+2/(x-2)] dx,用待定系数法分为2个分式
=(1/3)∫1/(x+1) d(x+1)+(2/3)∫1/(x-2) d(x-2)
=(1/3)ln(x+1)+(2/3)ln(x-2)+C
=∫x/[(x-2)(x+1)] dx
=(1/3)∫[1/(x+1)+2/(x-2)] dx,用待定系数法分为2个分式
=(1/3)∫1/(x+1) d(x+1)+(2/3)∫1/(x-2) d(x-2)
=(1/3)ln(x+1)+(2/3)ln(x-2)+C
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