求定义域，要详解
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lg[(5x-x^2)/4]>=0且(5x-x^2)>0
(5x-x^2)/4>=1
5x-x^2>=4
x^2-5x+4<=0
(x-1)(x-4)<=0
1<=x<=4
又5x-x^2)>0
x^2-5x<=0
x(x-5)<=0
0<=x<=5
综上得:1<=x<=4
(5x-x^2)/4>=1
5x-x^2>=4
x^2-5x+4<=0
(x-1)(x-4)<=0
1<=x<=4
又5x-x^2)>0
x^2-5x<=0
x(x-5)<=0
0<=x<=5
综上得:1<=x<=4
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