Question

问几道因式分解题目

½x²-2x+2=
x²-2x-3=
(x+1)(x+2)+¼=

Answer 1

解：1/2x²-2x+2
=2(1/4x²-x+1)
=2[(1/2x)²+2×1/2x×(-1)+(-1)²]
=2(1/2x-1)²
x²-2x-3,用十字相乘法分解
=(x+1)(x-3)
(x+1)(x+2)+1/4
=x²+3x+2+1/4
=x²+3x+9/4
=x²+2×x×3/2+(3/2)²
=(x+3/2)²

Answer 2

½x²-2x+2
=1/2(x²-4x+4)
=1/2(x-2)²

x²-2x-3
=(x+1)(x-3)

(x+1)(x+2)+¼=
=x²+3x+9/4
=1/4(4x²+12x+9)
=1/4(2x+3)²

Answer 3

½x²-2x+2=1/2(X-2)2(平方的意思)
x²-2x-3=(X-3)(X+1)
(x+1)(x+2)+¼=(X-3/2)2
小朋友继续努力吧

Answer 4

第一个-x+2 二个-x-3

Answer 5

½（X-2）²；（X-3)(X+1）；（x+3/2）²+1