Question

c语言求1+1/2+1/4+1/6+1/8+1/10+1/12+1/14+1/16+1/18+1/20？

Answer 1

    int i;

    float t,s=1;

    for (i=1;i<=10;i++){

        t = 1.0/(2*i);

        s += t;

        printf("%d %.4f %.4f\n",i,t,s);

    }

    printf("%f\n",s);

Answer 2

#include<stdio.h>
int main()
{
float sum=1;
for(int i=2;i<=20;i+=2)
sum+=1.0/i;
printf("%f",sum);
return 0;
}