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y'=[x+√(x²-1)]'/[x+√(x²-1)]
=[1+½·(x²-1)'/√(x²-1)]·[x-√(x²-1)]/[x²-(x²-1)]
=[1+½·2x/√(x²-1)]·[x-√(x²-1)]/1
=[1+x/√(x²-1)]·[x-√(x²-1)]
=√(x²-1)·[x+√(x²-1)]·[x-√(x²-1)]
=√(x²-1)·[x²-(x²-1)]
=√(x²-1)
=[1+½·(x²-1)'/√(x²-1)]·[x-√(x²-1)]/[x²-(x²-1)]
=[1+½·2x/√(x²-1)]·[x-√(x²-1)]/1
=[1+x/√(x²-1)]·[x-√(x²-1)]
=√(x²-1)·[x+√(x²-1)]·[x-√(x²-1)]
=√(x²-1)·[x²-(x²-1)]
=√(x²-1)
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