Question

化简三角函数

f(x)=sinx+cosx+√3cos2x-1
谢谢

Answer 1

cos 2x = cos^2 x - sin^2 x=1- 2 sin^2 x = 2cos^2 x - 1
f(x)=sinx + cosx + √3(cos^2 x - sin^2 x) - 1
=√3cos^2 x + cos x - √3sin^2 x + sin x - 1

Answer 2

f(x)=sinx + cosx + √3(cos^2 x - sin^2 x) - 1
=√3cos^2 x + cos x - √3sin^2 x + sin x - 1