Question

函数极限计算？

如图，请给出详细步骤

Answer 1

x->0
tanx = x+o(x^2)

ln(1+tanx)
=ln[1+x+o(x^2) ]
=x -(1/2)x^2+o(x^2)
x-ln(1+tanx) =(1/2)x^2+ o(x^2)