Question

若函数y=tanwx在区间(π/2,π)上单调递增,求实数w的取值范围

Answer 1

y=tanwx的单调递增区间为：kπ-π/2＜wx＜kπ+π/2,k∈Z在区间(π/2,π)上单调递增如果w＞0：wπ/2≥kπ-π/2,且wπ≤kπ+π/2即：2k-1≤w≤k+1/2∵w＞0,∴k≥1k≥2时2k-1＞k+1/2不合题意,舍去∴k=1∴1≤w≤3/2如果w...